Liquid Orifice Flow: Worked Example

Expected answer
171 US gpm

Calculate liquid flow through an orifice using an assumed discharge coefficient of 0.62. The upstream pipe has an actual inside diameter of 4.000 inches, the orifice bore is 2.000 inches, and the measured differential is 5 psi.

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1. Calculator Inputs

Select the units below before entering the numbers. These are fixed benchmark inputs for checking the calculator.

Calculator fieldValueUnit / setting
Solve forFlow rate
Discharge coefficient, Cd0.62dimensionless
Pipe inside diameter4in
Orifice bore diameter2in
Liquid density62.4lbm/ft³
Differential pressure5psi

2. Step-by-step Math

Convert the inputs

D = 4 × 0.0254 ≈ 0.102 m
d = 2 × 0.0254 ≈ 0.0508 m
ρ = 62.4 × 0.45359237 / 0.3048³ = 999.5521145 kg/m³
ΔP = 5 × 6894.757293168 ≈ 34,500 Pa

The 4-inch entry is an actual bore, not an NPS 4 Schedule 40 bore. Keep that distinction when reproducing this example.

Calculate the diameter ratio and orifice area

β = d/D = 0.0508 / 0.1016 = 0.5
1 − β⁴ ≈ 0.938
A = πd²/4 ≈ 0.00203 m²

The finite pipe-to-orifice area ratio is included. Omitting 1 − β⁴ changes the predicted flow.

Calculate and convert flow

Q = Cd A √[2ΔP / (ρ(1 − β⁴))]
Q = 0.62 × 0.00202682991639
    × √[2 × 34473.78646584 / (999.5521145 × 0.9375)]
Q = 0.0107790410923 m³/s
Q = 38.804547932 m³/h
Q = 0.0107790410923 / (0.003785411784/60)
Q ≈ 171 US gpm

Use the differential pressure corresponding to the meter and coefficient. It is not automatically the permanent pressure loss downstream.

3. Compare Your Answers

Keep full precision during the calculation. The calculator may display fewer digits; compare answers rounded to three significant figures; retain unrounded intermediate values.

ResultExpected answerYour answer
Flow rate171 gpm__________
Flow rate in SI38.8 m³/h__________
Beta ratio0.5__________
Orifice area0.00203 m²__________

Second check

Select Differential pressure and enter 170.851284468 gpm with the same geometry, density and Cd. The result should return 5 psi. At 20 psi, this fixed-Cd model predicts twice the original flow because Q varies with √ΔP.

4. Assumptions and Method

Single-phase incompressible liquid, with Cd supplied rather than calculated from Reynolds number or a meter standard. The example does not establish the correct coefficient or tap arrangement for a real meter. It omits gas expansion, cavitation, flashing and uncertainty analysis.

Equation definitions and implementation: Liquid Orifice Flow Calculator. See also calculation methodology and other worked examples.